3^2+40=-x^2-56

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Solution for 3^2+40=-x^2-56 equation: 



3^2+40=-x^2-56

We move all terms to the left:

3^2+40-(-x^2-56)=0

We add all the numbers together, and all the variables

-(-x^2-56)+49=0

We get rid of parentheses

x^2+56+49=0

We add all the numbers together, and all the variables

x^2+105=0

a = 1; b = 0; c = +105;
Δ = b2-4ac
Δ = 02-4·1·105
Δ = -420
Delta is less than zero, so there is no solution for the equation

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